What are the solutions to the equation 2(x+1)^2=32

Simplify 2(x+1)\times 22(x+1)×2 to 4(x+1)4(x+1).

4(x+1)=324(x+1)=32

2 Divide both sides by 44.

x+1=\frac{32}{4}x+1=

4

32

3 Simplify \frac{32}{4}

4

32

to 88.

x+1=8x+1=8

4 Subtract 11 from both sides.

x=8-1x=8−1

5/6

step-by-step explanation:

if i remember correctly with perpendicular stuff you just take away the negative

dnji

step-by-step explanation:

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