When 5 is subtracted from the square of a number ,the results is 4 times the number. find the negative solution

x=-1

Step-by-step explanation:

To find this

We assume the number is x

The square of the number=x^2

Therefore when 5 is subtracted from the number we get

x^2-5=4× the number x

x^2-5=4x

X^2-4x-5

To factorise

x^2-5x+x-5

(x^2-5x)+(x-5)

x(x-5)+1(x-5)=0

(x+1)(x-5)=0

To find the negative solution

(x+1)=0or (x-5)=0

x=-1

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation: