The difference of the square of a number and 28 is equal to three times the number find the negative solution

y=-4

Step-by-step explanation:

To find this

We get,

The difference between the square of the number

Let y be the unknown number

Square of y=y^2

Y^2-28=3y

Then let we are going to rearrange, then we get

y^2-3y-28

We are going to factorise

y^2-7y+4y-28

(y^2-7y+(4y-28)

y(y-7)+4(y-7)=0

(y+4)(y-7)=0

To find the negative number then we have

y=-4

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