Find the 34th term of the sequence 55, 51, 47, 43

- 77

Step-by-step explanation:

Note there is a common difference d between consecutive terms of the sequence, that is

51 - 55 = 47 - 51 = 43 - 47 = - 4

This indicates the sequence is arithmetic with n th term

= a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 55 and d = - 4, thus

= 55 + (- 4 × 33) = 55 + (- 132) = 55 - 132 = - 77

answer: i think it's a

step-by-step explanation: