Find the value of ‘k’ if one zero of p(x) = kx2
– 14 x + 8 is 6 times the other.

k = 3

Step-by-step explanation:

one zero of p(x) = kx²– 14 x + 8 is 6 times the other.

let the zeros are ⇒ a and 6a

the equation kx²– 14 x + 8

can be written as k ( x²/k– 14/k x + 8/k)

So, a * 6a = 8/k    ⇒ (1)

And a + 6a = 14/k ⇒ (2)

from (2)  k = 14/(a + 6a) = 14/(7a) = 2/a

∴ a = 2/k

Substitute at (1)

a * 6a = 8/k

2/k * 12/k = 8/k

solve for k

24/k = 8

k = 24/8 = 3

the value of k = 3

And the zeros will be 2/3 and 4

option 1

data plot with   3 dots over 33, 1 dot over 34, 2 dots over 35, no dot over 36, 1 dot over 37, 2 dots over 38, 4 dots over 39, and 2 dot over 40.

my guess is

step-by-step explanation: