The area of the rectangle is 3x2+6x-12square units. The length is x2+2x-4 What is the width of the rectangle?

delete for question misunderstood

Step-by-step explanation:

width (w) = 3

Step-by-step explanation:

The Area of a Rectangle = l * w

Where

l = length

w = width

From the question,

Area (A) = 3x²+6x-12

Length (l) = x² + 2x -4

To solve for width, let's rearrange the area.

A = 3x²+6x-12

A = 3 ( x²+ 2x -4)

From (A = lw)

Let's substitute the values:

3 ( x²+ 2x -4) = w * x² + 2x -4

Divide both sides by (x² + 2x -4)

3 = w.

Therefore, width (w) = 3

exa:

)

3+11

14

step-by-step explanation:

from this example, we can see that subtracting with integers is the same as adding the opposite. we can solve using a number line or by using the saying "keep, change, change" to us solve. it is important to remember that we can subtract a negative and end up with a larger number than we started with.

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°