Assume a recent sociological report states that university students drink 5.70 alcoholic drinks per week on average, with a standard deviation of 1.7201. Suppose Jason, a policy manager at a local university, decides to take a random sample of 170 university students to survey them about their drinking habits. Determine the mean and standard deviation of the sampling distribution of the sample mean alcohol consumption. Provide your answer with precision to two decimal places.

Mean= 5.70

Standard deviation= 0.132

Step-by-step explanation:

For the distribution of sample mean:

Mean of the sampling distrubution = \mu = 5.70

Standard deviation of the sampling distrubution = sigma/sqrt{n} = 1.7201 /sqrt{170} = 0.132

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.

ok then what happened.