Consider the equations: y = 3x + 2 and y = 2x + 1.
Solve the system of equations by completing the table of values to find an ordered pair that satisfies both equations.
(-1, -1)
(0,2)
(1,5)
(2,8)

(-1, -1)

Step-by-step explanation:

First, both equations are equal to y, so we can substitute one equation for y in the other equation.

1. 3x + 2 = 2x + 1

Next, we need to add or subtract like terms from each side.

2. 3x + 2 = 2x + 1

 -2x    -2   -2x   -2

            x = -1

We found x. Now we can plug in x to one equation to find y.

3. y = 2(-1) + 1

   y = -2 + 1

   y = -1

To make sure it works, let's plug in y to one of the equations.

4. -1 = 2x + 1

   -1          -1

   -2/2 = 2x/2

   -1 = x

d

step-by-step explanation:

i used the pitagoras theoreme

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116