f(1)=3f(1)=3 and f(n)=2f(n-1)+3

f(n)=2f(n−1)+3

then find the value of f(3)

f(3)=21

Step-by-step explanation:

f(1)=3

f(n)=2f(n-1)+3

n=2

f(2)=2f(2-1)+3

f(2)=2f(1)+3

f(2)=2*3+3

f(2)=6+3

f(2)=9

n=3

f(3)=2f(3-1)+3

f(3)=2f(2)+3

f(3)=2*9+3

f(3)=18+3

f(3)=21

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

don't report but were is the digram

step-by-step explanation: