Which of the following sequences of transformation is used to obtain figure A’B’C’D’ from ABCD?

Most likely (B)

Step-by-step explanation:

Points of ABCD:

A (3,1)

B (3,4)

C (5,5)

D (5,2)

The algebraic rule for reflecting across the y axis:

(x,y) ---> (-x, y)

Points of ABCD after being reflected: (shown by figure 2)

A (-3, 1)

B (-3, 4)

C (-5, 5)

D (-5, 2)

Then, the figure got translated two units to the left, resulting in figure F in the picture, and A’B’C’D’ in the question.

Points of ABCD after being translated by (x-2, y) : (shown by figure F)

A (-5, 1)

B (-5, 4)

C (-7, 5)

D (-7, 2)

This should be the coordinates of A’B’C’D’.

i can't solve unless i know what the line is

step-by-step explanation:

welcome to/p>

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)