Sue left her home at 9 am and walked to the library.
She got to the library at 10:30 am.
Sue walked at a speed of 3mph.
What distance did sue walk?

Step-by-step explanation:

This is a simple motion problem, d = rt.  We are asked what distance she traveled, so we need to figure out the values to put in for r and for t.  

We know that the rate she walked was 3mph.  The time is found by figuring out how long it took her to walk to the library if she left at 9 and got there at 10:30.  That is, in hours, 1.5.  Filling in our motion problem with these values:

d = 3(1.5) tells us that

d = 4.5 miles

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

51-50

step-by-step explanation: