In trapezoid $ABCD,$ $\overline{AB} \parallel \overline{CD}$, and $AB < CD.$ The base $\overline{CD}$ has a length of $8.$ The legs $\overline{AD}$ and $\overline{BC}$ have lengths of $7,$ and the diagonal $\overline{BD}$ has a length of $9.$ Find the area of the trapezoid.

step-by-step explanation:

the answer is 1/4

step-by-step explanation:

hello 0xxbadwolfxx0,

2.6 x 10^9 is 2,600,000,000.

1.3 x 10^2 is 130

multiplying 130 and 2,600,000,000 would simply give you 200,000,000,000.

therefore, the answer would be d. 2.0 × 10^11.

i hope i ! warm regards, mae.