If ABCD is dilated by a factor of 3, the coordinate of C' would be:

The coordinates of C' would be (9, 9).

Solution:

The coordinate of C = (3, 3)

Scale factor (k) = 3

ABCD is dilated by a factor 3.

If a figure dilated by a scale factor of k with a center of dilation at the origin, then

The coordinates of C' are

The coordinates of C' would be (9, 9).

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.