Use the elimination method to solve the system of equations. Choose the correct ordered pair. 5x+3y=31 2x+3y=25

(2,7)

Step-by-step explanation:

5x+3y=31

2x+3y=25

Multiply the second equation by -1

-2x -3y = -25

Add this to the first equation

5x+3y=31

-2x-3y=-25

3x  = 6

Divide each side by 3

3x/3 = 6/3

x =2

Now we need to solve for y

5x+3y = 31

5*2 +3y = 31

10+3y = 31

Subtract 10 from each side

10-10 +3y = 31-10

3y = 21

Divide by 3

3y/3 = 21/3

y= 7

x = 2

y = 7

Step-by-step explanation:

in order to solve this system of equation using elimination method we say let

5x+3y=31 equation 1

2x+3y=25 equation 2

step 1

you are going to add -1 to equation 2 so u can have a negative sign

2x+3y=25 equation 2

-1 (2x) + -1(3y) = -1(25)

after multiplying we have

-2x - 3y = -25  equation 3

Step 2

add equation 1 and equation 3 together

5x+3y=31 equation 1

+

-2x - 3y = -25  equation 3

we have,

3x = 6

divide both sides by the coefficient of x which is 3

we have ,

3x/3 = 6/3

x = 2

put the value of x = 2 in equation 2

2x+3y=25 equation 2

2(2) + 3y = 25

4 + 3y = 25

collect the like terms

3y = 25 - 4

3y = 21

divide both sides by 3

3y/3 = 21/3

y = 7

therefore the value of x = 2 and value of y = 7 respectively.

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