If $8,000 is invested at an annual interest rate of 1.83%, compounded daily, what will the investment be worth after 10 years?

$9606.41

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1 + r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = $8000

r = 1.83% = 1.83/100 = 0.0183

Assuming there are 365 days in a year, then

n = 365 because it was compounded 365 times in a year.

t = 10 years

Therefore,

A = 8000(1 + 0.0183/365)^365 × 10

A = 8000(1 + 0.000050137)^3650

A = 8000(1.000050137)^3650

A = $9606.41

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1