You are constructing a frame for another copy of the photo. You want the frame to be the same width all the way around and the total area of the frame and photo to be 391 in.2. What should the outer dimensions of the frame be?

Outer dimension is 19.77 in by 19.77 in

Step-by-step explanation:

Since the width is intended to be the same all round, it is a square

Hence W x W = 391in²

W² = 391

W = √391 = 19.77 in

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

step-by-step explanation:

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