Find the equation of the line that is perpendicular to y = –13x + 2 and passes though the point (–5, 2).

The answer to your question is   y = -1/13x + 21/13

Step-by-step explanation:

Data

⊥ to y = -13x + 2

Point = (-5, 2)

Process

1.- Find the slope of the original line

The slope is the coefficient of the x in the equation line

               y = -13x + 2      

For this equation -13 is the slope

2.- Find the slope of the new line

As the lines are ⊥, the slope are reciprocal

     new slope = -1/13

3.- Find the equation of the line

            y - y1 = m(x - x1)

-Substitution

           y - 2 = -1/13(x + 5)

-Simplification

           y - 2 = -1/13x - 5/13

           y = -1/13x - 5/13 + 2                          

           y = -1/13s + (26/13 - 5/13)

-Result

           y = -1/13x + 21/13

answer: the answer is ann