Eduardo and Sarawong are selling wrapping paper for a school fundraiser. Eduardo sold 5 rolls of plain wrapping paper and 5 rolls of holiday wrapping paper for a total of $185. Sarawong sold 14 rolls of plain and 5 rolls of holiday for a total of $338. Find the cost per roll of plain wrapping paper and 5 rolls of holiday wrapping paper.

A roll of plain wrapping paper costs $17, while a roll of holiday wrapping paper costs $20.

Step-by-step explanation: First let us represent a roll of plain wrapping paper with letter p and a roll of holiday wrapping paper would be represented by d. If Eduardo sold 5 rolls of plain wrapping paper and 5 rolls of holiday wrapping paper for $185, then we can express this as

5p+ 5d= 185

Also if Sarawong sold 14 rolls of plain wrapping paper and 5 rolls of holiday wrapping paper for $338, then this too can be expressed as

14p + 5d = 338

Now we have a pair of simultaneous equations which are,

5p + 5d = 185 ———(1)

14p + 5d = 338 ———(2)

Since all the variables have coefficients greater than 1, we shall use the elimination method. Note that the coefficients of the d variable are both 5, so straight away we subtract equation (1) from equation (2) and we now have;

(14p - 5p) + (5d - 5d) = 338 - 185

9p = 153

Divide both sides of the equation by 9

p = 17

Having calculated p, we can now substitute for the value of p into equation (1)

5p + 5d = 185

5(17) + 5d = 185

85 + 5d = 185

Subtract 85 from both sides of the equation

5d = 100

Divide both sides of the equation by 5

d = 20

Hence, the cost per roll of plain wrapping paper is $17, while the cost per roll of holiday wrapping paper is $20.

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^

{3 + i, 3 - i, 3, -1}

step-by-step explanation: