Find the length and width of the actual room. The length is 6.5 in the width is 5 in and the scale is 3 in 8ft Use the information to find the area of the actual room

The length of the actual object is = 17.33ft or 17ft 4in

The width of the actual object is = 13.33ft or 13ft 4in

Step-by-step explanation:

A scale drawing basically refers to the drawing that displays an object with the actual sizes increased or reduced by a particular amount. For example, if we are required to draw a nine - storey building on paper, it may not be possible to find any paper that will be able to accommodate the actual size of the nine - storey building; Even if there is, it will be so inconvenient to carry around. What is done in most cases is to use a scale to reduce the actual size of the building while still retaining all the necessary details of the building on the drawing paper.

Now, since the scale used for the drawing of the model room is 3in : 8ft , it means that every 8 feet in the size or dimension of the actual drawing will be represented by 3 inches on the drawing paper.

For the length of the model room which is 6.5 inches, the true dimension of the actual object is:-

3 inches 8 feet

6.5 inches ? feet

= 6.5/3 × 8

= 52/3

= 17.33 feet (length of the actual object)

For the width of the model room which is 5 inches, the true dimension of the actual object is:

3 inches 8 feet

5 inches ? feet

5/3 × 8

= 40/3

= 13.33 feet (width of the actual object)

Since one foot is = 12 inches; 0.33 feet is =

0.33 × 12 = 4inches

Therefore, the length of the actual object is 17.33 feet or 17ft 4in

&

The width of the actual object is 13.33 feet or 13ft 4in

answer: i'm great at algebra

~coco

step-by-step explanation:

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!