How will the product change if: a one factor is decreased 2 times, and the other is decreased 8 times

The product of two factors will be decreased 16 times if one factor is decreased 2 times and the second factor is decreased 8 times.

Step-by-step explanation:

Before we can determine how the product of the two factors will change, let us denote one of the factors in question by "m" and the second factor by "n".

The product of these two factors before they are decreased is simply:-

m × n

Now, if the first factor (m) is decreased two times, we will simply divide it by two and the result that would be obtained is:

m/2

Similarly, when the second factor (n) is decreased eight times, we will divide it by eight (8) and obtain:-

n/8

After decreasing the factors two times and eight times respectively, their products will now be equal to:

m/2 × n/8 = m /16

Therefore, the product of two factors will be decreased sixteen times (16 times) if one factor is decreased two times (2 times) and the other is decreased eight times (8 times).

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3