Hypotenuse of triangle with sides of 36 and 39

The hypotenuse is 53 (approximately)

Step-by-step explanation: In this question we shall apply the Pythagoras theorem which states that;

AC^2 = AB^2 + BC^2

Where AC is the hypotenuse and AB and BC are the two other sides. Having been given that the two other sides are 36 and 39 units respectively, the hypotenuse is now,

AC^2 = 36^2 + 39^2

AC^2 = 1296 + 1521

AC^2 = 2817

Add the square root sign to both sides of the equation

AC = 53.0754

Therefore the hypotenuse is approximately 53 units.

complete the steps to find the area of the trapezoid.

area of rectangle = 256   square units

area of triangle 1 = 24  square units

area of triangle 2 = 16  square units

area of triangle 3 =   96 square units

area of trapezoid = 120  square units

step-by-step explanation:

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!