In the system shown below, what are the coordinates of the solution that lies in quadrant II? Write your answer in the form (a, b) without using spaces

x^2+4y^2=80

y=1/32x^2

The pair is (-8, 2

Step-by-step explanation:

Allow me to rewrite the system shown below:

<=>

and y = (1)

Substitute into equation (1), we have:

y = ( )

<=> 32y = 80 -

<=> + 32y -80 = 0

<=> y = 2 and y = -10

When y = 2 we have: x= 8 or x = -8

When y = -10, we have no x

Because the coordinates of the solution that lies in quadrant II, so we delete the value of  x =  8

So the pair is (-8, 2)

i think the answer would be c