A-b)3+(b-c)3+(c-a)3:(a-b)(b-c)(c-a)

The answer to the above equation is 3

Step-by-step explanation:

(a-b)³+(b-c)³+(c-a)³: (a-b)(b-c)(c-a)

Let us consider  (a−b)= x, (b−c)= y and (c−a)= z.  

Hence, It is obvious that:

x+y+z =0 ∵all the terms gets cancelled out

⇒We must remember the algebraic formula

x³+y³+z³−3xyz= (x+y+z) (x²+y²+z²-xy-xz-yz)

Since x+y+z=0 ⇒Whole “(x+y+z) (x²+y²+z²-xy-xz-yz) ” term becomes 0

x³+y³+z³−3xyz =0

Alternatively, x³+y³+z³= 3xyz

Now putting the value of x, y, z in the original equation

(a-b)³+(b-c)³+(c-a)³ can be written as 3(a-b)(b-c)(c-a) since  (a−b)= x, (b−c)= y and (c−a)= z.

3(a-b)(b-c)(c-a): (a-b)(b-c)(c-a)

= 3           ∵Common factor (a-b)(b-c)(c-a) gets cancelled out

Answer to the above question is 3

answer: this doesnt make any sense especially the photo.

step-by-step explanation:

rick has $1400 and sally has $1500

step-by-step explanation:

to find amount of money rick has after 10 years :

principal = $1000 , time = 10 years , rate = 4% annually

to find amount of money sally has after 10 years :

her friend gives to pay her $50 per year, therefore money she has after 10 years = 50 × 10 = $500

also, sally gets $1000 after 10 years,

therefore, total amount of money sally has after 10 years = 500 + 1000 = $1500

so, after 10 years : rick has $1400 and sally has $1500