3sin(4x)+5=6 Solve the following equation over the interval [0, pie/2)
a- x=1/4arcsin(1/3) , x=pie-1/4arcsin(1/3)
b- x=1/4arcsin(2/3) , x=pie-1/4arcsin(2/3)
c- x= arcsin(2/3) , x=pie-arcsin(2/3)
d- x=arcsin(1/12) , x= pie-arcsin(1/12)
e- x=1/4arcsin(1/3) , x= pie/4-1/4arcsin(1/3)
I was able to get x= 1/4arcsin(1/3) for one of my answers(I am not sure if it is right) but I am having trouble finding the other answer. Help?