The average outstanding bill for delinquent customer accounts for a national department store chain is $187.50 with standard deviation $54.50. In a simple random sample of 50 delinquent accounts, what is the probability that the mean outstanding bill is over $200?

P(x > 200) = 0.053

Step-by-step explanation:

Assuming a normal distribution for the outstanding bill for delinquent customer accounts for the national department store chain, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ/√n

Where

x = outstanding bill for delinquent customer accounts.

µ = mean

σ = standard deviation

n = number of samples

From the information given,

µ = $187.50

σ = $54.50

n = 50

The probability that the mean outstanding bill is over $200 is expressed as

P(x > 200) = 1 - P(x ≤ 200)

For x = 200,

z = (200 - 187.5)/54.5/√50 = 1.62

Looking at the normal distribution table, the probability corresponding to the z score is 0.947

P(x > 200) = 1 - 0.947 = 0.053

it could 14.28 but if its not that one then it has to be the 17 one. hope this ! : )

step-by-step explanation:

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.