Noah has 50 feet of fencing to completely enclose a rectangular garden in the backyard. Find the length and width of a rectangle that would produce the largest possible area

Length = 12.5 feet

Width = 12.5 feet

Step-by-step explanation:

We can set two equations to solve this problem.

First equation:

The perimeter of a rectangle is 2*L + 2*W, where L is the lenght and W is the width, and Noah has 50 feet of fencing to use, so:

2*L + 2*W = 50

Second equation:

The area of the rectangle (A) is calculated mutiplying the lenght by the width:

A = L * W

Dividing the first equation by 2 and isolating L, we have:

L + W = 25 -> L = 25 - W

Using this equation in the second one, we have:

A = (25 - W)*W = 25W - W^2

The formula to calculate the point that gives the maximum value is:

x = –b/2a

So, the value of W that gives the maximum area will be:

W = -25/2*(-1) = -25/(-2) = 12.5 feet

Using this value in the first equation W + L = 25, we have:

12.5 + L = 25

L = 12.5 feet

So, the length and width that produce the largest possible area are 12.5 feet and 12.5 feet.

answer: 10 meter

step-by-step explanation:

need details

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.