A spherical scoop of vanilla ice cream with radius of 2 inches is dropped onto the surface of a dish of hot chocolate sauce. As it melts, the ice cream spreads out uniformly forming a cylindrical region 8 inches in radius. Assuming the density of the ice cream remains constant, how many inches deep is the melted ice cream

1/6in

Step-by-step explanation:

In order to find the height of the melted ice-cream, first we need to find volue of a sphere then a cylinder and equate them.

As we know, the volume of a sphere is defined as:

 V = (4/3)π·r³

therefore, scoop has:

 V = (4/3)π·(2 in)³ => 32π/3 in³

Next is to find the volume of a cylinder

V = π·r²·h=> π·(8 in)²·h

Since the cylinder has the same volume as the sphere, we have

 32π/3 in³ = π·(8 in)²·h   (simplifying the equation)

 We have, h = (32π in³)/(3x64π in²) = 1/6 in

h=1/6in

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

answer:

c) the x-coordinate of the center of the circle increases by 3