The perimeter of this rectangle and area, and if the area was 100 what would the value of x be, also if the area is 200, what is the value of x. thank you so much to whoever answers

Given:

Length of the rectangle = x + 21

Width of the rectangle = 5

To find:

Perimeter and area of the rectangle

Solution:

Perimeter =

Perimeter units

Area = length × width

Area square units

Substitute perimeter is 100 and find the value of x:

Subtract 52 from both sides.

Divide by 2 on both sides, we get

x = 24

Substitute area is 200 and find the value of x:

Subtract 105 from both sides.

Divide by 5 on both sides, we get

x = 19

If the perimeter is 100, then the value of x is 24.

If the area is 200, then the value of x is 19.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

560

step-by-step explanation:

giggidy