Please help with two- Way Frequency tables (picture attached)

Let's start with the column and row totals, which should make things easier

Total <$20K = 69+112+102+13 = 296

total $20-30K  500

total >30K   404

TOTAL 296+500+404=1200

Rows,

<HS   69+36+2 = 107

HS 224

Some C  438

C     431

Check total: 107+224+438+431 = 1200, good

A. P(<HS)  = 107/1200

because there are 107 folks who didn't finish high school out of the 1200 total.

B.  P(<$20K) = 296/1200 = 37/150

C.  P(>$30K & <HS)

Only 2 of 1200 folks fit this description, upper right box.

P(>$30K & <HS) = 2/1200 = 1/600

D.  P(<$20K & C) = 13/1200

That's the bottom left box.

E. P(>$30K & HS) = 14/1200 = 7/600

F. P(<HS OR >$30K)

OR is usually more complicated.  We have 107 who didn't finish high school and 404 more than $30K.   We counted the 2 in the box <HS AND >$30K twice, so our total is 107 + 404 - 2 = 509

P(<HS OR >$30K) = 509/1200

d

step-by-step explanation:

hello and welcome!

so, when we see the words "proportional" along with a table, we need to know that we're looking numbers that divide by the same thing.

looking at this table, we simply have to do a trial and error, and divide to see which numbers have the same quotient. if you look at choice a & c, they both have equal quotients for three of the numbers, with one exception, so those can't be the answer. looking at b, there is no similarity, so that can't be it. then, we see d; if you divide all the numbers in the table, you'll see that they all divide by two, which is a proportional relationship, and our answer!

also, always remember that the x will always be the number that goes into y, and somewhere behind this table, is a formula. for this specific table, the formula would be:

since our x-value is being divided by two to get the y-value. and if they were to ask for more numbers in the series, this is the formula you would use to find them.