Use determinants to find out if the matrix is invertible.

[ -5 0 1
-1 3 2
0 10 6 ]

The matrix is not invertible.

Step-by-step explanation:

We are given the following matrix in the question:

Condition for invertible matrix:

A matrix is invertible if and only if the the determinant is non-zero.

We can find the determinant of the matrix as:

Since the determinant of the given matrix is zero, the given matrix is not invertible.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

c

step-by-step explanation:

i think because what else can be a sample of every member