A researcher reports that the mean time it takes to complete an experimental task is 1.4 ± 8.0 (M ± SD) s. If the null hypothesis was that the mean equals 1.0, then what is the effect size for this test using estimated Cohen’s d? Group of answer choices

The Cohen's d effect size is 0.05.

Step-by-step explanation:

The Cohen's d effect size is a numerical value that indicates the standardized difference between two means.

It is provided that the mean time to complete an experimental task reported by the researcher is,

Since the standard deviation of the population is not provided we will use a one-sample t - test to perform the analysis.

The formula of Cohen's d effect size in case of one-sample t - test is:

Compute the value of Cohen's d effect size as follows:

Thus, the Cohen's d effect size is 0.05.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

step-by-step explanation:

for volume, add base x height x width