The path of a total solar eclipse is modeled by f (t )equals 0.00223 t squared minus 0.558 t plus 41.395, where f(t) is the latitude in degrees south of the equator at t minutes after the start of the total eclipse. What is the latitude closest to the equator, in degrees, at which the total eclipse will be visible.

Therefore the latitude closest to the equator is 6.49°(approx).

Step-by-step explanation:

Given the path of a solar ellipse is modeled by

where f(t) is the latitude in degrees south of the equator at t minutes.

We know that ,

The minimum or maximum value of a function y(t) =at²+bt+c

is when

In this case a= 0.00223, b= - 0.558  and c= 41.395.

The minimum value of f(t)

when

           =125.11

Therefore the latitude closest to the equator is

f(125.11)=0.00223(125.11)²-0.558×125.11+41.395

            ≈6.49

rotated. i took the test

step-by-step explanation:

12/11c

or

12

c

11