Prove that the diagonals of a parallelogram bisect each other.
The midpoint of AC is
A. (a+2b, c)
B.(a+b/2, c/2)
C.(2a+2b,2c)
D.(a+b, c)

answer: the resulting cross section is a rectangle. solution: a plane parallel to the base of a triangular prism will intersect a cross section that is the same shape as its bases. so the cross section is a triangle.

step-by-step explanation:

explanation:

remove parenthesis:

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apply rule

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multiply fractions:

=

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divide:

=

mordancy.

the height of the surface increases from the center out to the sides of the road.

step-by-step explanation:

as we move out we move away from the x-axis.

and as mentioned in the problem statement that height of a road increases when we move away from the center x.

hence proved that 3rd option

the height of the surface increases from the center out to the sides of the road.

is the correct option.