A pizza stand offers both hand-tossed and pan pizza. Customers can add any combination of the six available toppings.

a)14 or b)74

Step-by-step explanation:

I'm assuming the question is how many combinations are there.

A) If toppings can't stack it would be 14, since there are 6 toppings for 2 pies and also you can go without toppings. or *2

B) If toppings can stack, then there can be 74 from being able to stack 6 toppings on one pizza and then two pizzas without it or (6^2)*2+2

asnwer is (g o h o f)(x) = 2x - 6/x + 7

step-by-step explanation:

given,

f(x) = x - 3/x

g(x) = x + 3

h(x) = 2x + 1

we need to find : (g o h o f)(x)

we can write (g o h o f)(x) = g[ h{ f(x) } ]

so first we find h{f(x)}

h{f(x)} = f(x) + 3 = (x - 3/x) + 3

h{f(x)} = x - 3/x + 3

now we find g[ h{ f(x) } ].

g[ h{ f(x) } ] = g(x - 3/x + 3)       {plug h{f(x)} = x - 3/x + 3 in g[h{f(x)}] }

g(x - 3/x + 3) = 2 (x - 3/x + 3) + 1

                    = 2x - 6/x + 6 + 1

                    = 2x - 6/x + 7

hence we get (g o h o f)(x) = 2x - 6/x + 7

a king of hearts and a 2 of spades