What are the new vertices of parallelogram DEFG if the parallelogram is reflected across the vertical line x = -2, also graphed?

B

Step-by-step explanation:

Since x = - 2 is the line of reflection then the coordinates of the image will be the same distance in the x- direction from x = 2 but on the opposite side.

The y- coordinates of the points remain unchanged.

D is 3 units left of x = - 2 thus D' is 3 units to the right of x = - 2

E is 1 unit left of x = - 2 thus E' is 1 unit to the right of x = - 2

F is 1 unit left of x = - 2 thus F' is 1 unit to the right of x = - 2

G is 3 units left of x = - 2 thus G' is 3 units to the right of x = - 1

Thus

D(- 5, 5 ) → D'(1, 5 )

E(- 3, 3 ) → E'(- 1, 3 )

F(- 3, - 4 ) → F'(- 1, - 4 )

G(- 5, - 2 ) → G'(1, - 2 )

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places