The vertices of a triangle are p(-1, 3), q(2, -1), and r(5, 3).

choose all of the congruent sides of the triangle.

pq
pr
qr

Ok so to find which sides are congruent we need to know their lengths.

To find the length we need the distance formula between two point ->

√(X2-X1)∧2 +(Y2-Y1)∧2

Ok lets find the first side PQ

P(-1,3) Q(2,-1)
   X1 Y1  X2 Y2

√(2-(-1)∧2 + (-1-3)∧2 = 5

Now PR

P (-1,3) R (5,3)
    X1 Y1  X2 Y2

√(5-(-1))∧2 + (3-3)∧2) = 6

Now the last side QR

Q (2, -1) R (5,3)
   X1  Y1    X2 Y2

√(5-2)∧2 + (3-(-1))∧2 = 5

From the above work we see that PQ and QR are congruent becuase they are equal PQ=QR

Also the opposite angles of these sides are congruent. Hope this helps :).

I’m pretty sure the answer is counter steer.