Suppose
y = , where x and y are functions of t.
If dy/dt = 4, find dx/dt when x = 12.

The value of is 20

Explanation:

Given that the expression is

We need to determine the value of when

Value of :

Let us differentiate both sides of the equation with respect to t.

Thus, we have,

Applying the chain rule, we get,

Differentiating, we get,

Simplifying, we get,

Now, we shall determine the value of when

Substituting and , we have,

Simplifying the values, we get,

Thus, the value of is 20

20

Step-by-step explanation:

dy/dx = [½(2x + 1)^-½]×2

= 1/[(2x+1)^½]

At x = 12

1/(25^½) = 1/5

dy/dx = dy/dt × dt/dx

⅕ = 4 × dt/dx

dx/dt = 4 ÷ ⅕

= 4 × 5

= 20

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.