A circle is centered at R(2,4)R(2,4)R, (, 2, comma, 4, ). The point L(0,8)L(0,8)L, (, 0, comma, 8, )is on the circle. Where does the point Q(6,7)Q(6,7)Q, (, 6, comma, 7, )lie?

The point Q(6,7) lie outside the circle.

Step-by-step explanation:

We know that, the general equation of a circle,

  ---------(1)

Centre is (-g, -f) = (2,4) (given)

So, -g = 2⇒g = -2

and, -f = 4⇒f = -4

Putting the value of g and f in equation(1), we get

The point L(0,8) is on the circle, the this point can satisfy the above equation.

So,

Now, the equation of circle is

Putting the and in the above equation, we get

5, which is greater than 0.

So, the point Q(6,7) lie outside the given circle.

answer: it is 8

step-by-step explanation:

you know why its 8

b. f(x) = –√x + 3this is the correct answer