1. Given a regular octagon, find the measures of the angles formed by (a) two consecutive radii and (b) a radius and a side of the polygon. a. 40°; 230° b. 45°; 67.5° c. 72°; 252° d. 36°; 216°

(B)45°, 67.5°

Step-by-step explanation:

A regular polygon is a polygon in which all the sides are equal.

An Octagon is a polygon with 8 sides.

Since it is a Regular polygon, the following holds:

1.The Radii are equal

2. The angle Subtended by two radii are equal for all triangles in the octagon.

3. There are 8 Isosceles triangles in the octagon.

(a)Measures of angle formed by Two radii

From the centre of the octagon, there are 8 equal angles.

Sum of Angle at a point= 360°

Each Angle=360°÷ 8 = 45°

The measures of angle formed by two radii is 45°.

(b)a radius and a side of the polygon.

Since the triangles are Isosceles, the base angles at the side of the octagon are equal.

Let x be the angle made by a radius with a side.

From (a) above,

x+x+45°=180°(Sum of Angle in a Triangle)

2x=180-45°

2x=135°

x=135°÷2=67.5°

The angle between a radius and a side of the polygon is 67.5°.

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068