The braking distance in feet of a car traveling at v miles per hour is given by d=1/20v^2 + 2.2v
A. what is the breaking distance in feet if the car is going 30 mph
B. Suppose that the car took 500 feet to break use your computations in part (a) to make a prediction about how fast it was going when the breaks were applied.

B. 500

Step-by-step explanation:

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Answers

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a. What is the braking distance, in feet, if the car is going 25 mph? 55 mph? 85mph? Show your work.

At 25 mph, braking distance = d=2.6(25)+(252/22)= 93.41mph

At 55 mph, braking distance = d=2.6(55)+(552/22)= 280.5 mph

At 85 mph, braking distance = d=2.6(85)+(852/22)= 549.41mph

b. Suppose that the car took 450 feet to brake. Use your computations in part (a) to

make a prediction about how fast it was going when the brakes were applied.

c. Graph the distance equation to determine more precisely how fast it was going when the brakes were applied, and plot your calculated results from above onto your graph. Discuss your findings.

From our answers in part (a), we see that the speed for a braking distance of

500 ft is between 55 mph and 85 mph. Estimates within this range can vary,

though based on the computations,

Step-by-step explanation:

Edge

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!