A manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective independently. A box of 150 bulbs is selected at random. Answer the following questions. Check the conditions of the Binomial setting using the information from.

(a) The probability that the box contains at most 20 defective bulbs is 0.9131.

(b) The expected number of defective bulbs in the box is 15.

(c) The standard deviation of the number of defective bulbs is 3.67.

Step-by-step explanation:

Let X = number of defective bulbs.

The probability of selecting a defective bulb is, p = 0.10.

The box consists of n = 150 bulbs.

The random variable X follows a Binomial distribution with parameters n = 150 and p = 0.10.

Normal approximation to binomial can be applied here because:

So X follows a Normal distribution with,

Mean:

Standard deviation:

(a)

Compute the probability that the box contains at most 20 defective bulbs as follows:

Thus, the probability that the box contains at most 20 defective bulbs is 0.9131.

(b)

Compute the expected number of defective bulbs in the box as follows:

Thus, the expected number of defective bulbs in the box is 15.

(c)

Compute the standard deviation of the number of defective bulbs as follows:

Thus, the standard deviation of the number of defective bulbs is 3.67.

triangle abc is reflected on the line x=-6.5 then reflected again on the x axis

step-by-step explanation:

1/3

step-by-step explanation:

to find this, you can divide 12 by 4 which is 3 or you can multiply 4 until you reach 12 (4x3=12). both should give you 3, meaning theres three times less bananas than there are oranges.