Trigonometry
Objective: Use trigonometry functions to find the area of triangles.
In ΔABC, AB=21, AC=16, and m< A=67*. Find the area of ΔABC, to the nearest tenth of a square unit.

The area of the triangle ABC is 154.6 square units

Explanation:

Given that the measurements of the sides of the triangles are , and

We need to determine the area of the triangle ABC

Area of triangle ABC:

The area of the triangle can be determined using the formula,

Substituting the values, we get,

Simplifying the terms, we get,

Multiplying the values, we have,

Dividing, we get,

Rounding off to the nearest tenth, we get,

Thus, the area of the triangle ABC is 154.6 square units

answer: i think it's a

step-by-step explanation:

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!