Austin invested his saving in two investment found the amount he invested in fund A was 3 times as much as the amount he invested in Fund B. Fund A really returned a 6% profit and Fund B returned a 2% profit. How much did he invest in Fund B, if the total profit from the two funds together was $1800

he invested $9000 in Fund B

Step-by-step explanation:

Let x represent the amount which he invested in the account returning 6% profit.

Let y represent the amount which he invested in the account returning 2% profit.

The amount he invested in fund A was 3 times as much as the amount he invested in Fund B.. This means that

x = 3y

The formula for determining simple interest is expressed as

I = PRT/100

Considering the account returning 6% profit,

P = $x

T = 1 year

R = 6℅

I = (x × 6 × 1)/100 = 0.06x

Considering the account paying 2% interest,

P = $y

T = 1 year

R = 2℅

I = (y × 2 × 1)/100 = 0.02y

if the total profit from the two funds together was $1800, it means that

0.06x + 0.02y = 1800 - - - - - - - - - -1

Substituting x = 3y into equation 1, it becomes

0.06 × 3y + 0.02y = 1800

0.18y + 0.02y = 1800

0.2y = 1800

y = 1800/0.2 = 9000

x = 3y = 3 × 9000

x = 27000

42%

step-by-step explanation:

we know,

total people = 60

total males = 25

percentage of males

= 25/60 × 100

= 25/6 × 10

= 25/3 × 5

= 125 / 3

= 41.

rounding of = 42%

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answer for #1 is c

answer for #2 is d

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