A new surgery is successful 85% of the time. If the results of 6 such surgeries are randomly sampled, what is the probability that fewer than 4 of them are successful

The probability that fewer than 4 of them are successful are 0.9527

Explanation:

Given:

number of trials, n = 6

p(successful) = 0.85

P(x >= 4) = ?

The problem can be solved using binomial probability formula.

 P(x >= 4) = 1 - binomcdf(6,0.85,4) = 1 - 0.0473

               = 0.9527

Therefore, the probability that fewer than 4 of them are successful are 0.9527