T takes 10 road workers 5 days to complete a road repair when working 2 hours a day. Working at the same pace, how many days will it take 2 people working 5 hours a day to finish it?

The no. of days required to finish the work = 10 days

Step-by-step explanation:

In first case :-

No. of workers = 10

No. of days = 5

No. of hours taken = 2 hours

In second case :-

No. of workers = 2

No. of days = ??

No. of hours taken = 5 hours

We know that

⇒ =

⇒ Put all the values in above formula we get

⇒ 10 × 5 × 2 = 2 × × 5

⇒ = 10 days

Thus the no. of days required to finish the work = 10 days

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0