Which shows the given inequalities in slope-intercept form?

Solve for X      

4x−5y<1

Step-by-step explanation:

step 1 add 5y to each side

4x−5y+5y<1+5y

4x<5y+1

Step 2: Divide both sides by 4.

4x4<5y+14

x<54y+14

x<54y+14

Let's solve for x.

12y−x<3

Step 1: Add (-1)/2y to both sides.

−x+12y+−12y<3+−12y

−x<−12y+3

Step 2: Divide both sides by -1.

−x−1<−12y+3−1

x>12y−3

x>12y−3

now just graph 4x-5y<1 shows the given inequalities in slope -intercep form.

whats the question?

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)