25 points PLEASE HELP NOW
DUE TODAY

440

Step-by-step explanation:

Her we have two objects: 2 square.

1st has dimension 5x5x8

2nd has dimension 10x10x2

But we also have invisible prarts, the bottom of 1st is on the top od the 2nd. So we will remove something.

The formula for the surface of the square is

S=2B+M

Surface area of the first is

S1=2x5x5+4x8x5=50+160=210

Surface are of the 2nd is

S2=2x10x10+4x10x2=200+80=280

S=s1+s2-50=210+280-50=440

This -50 is are od one base from first square 5x5=25 whic we added in s1, but in real it is invisible.

The same area we added in s2. The top is 10x10-5x5 (invisible prat).

So we added two times 25, it is 50.

surface area = 440 in²

Step-by-step explanation:

The given solid is made up of two cuboids. The formula for determining the surface area of a cuboid is expressed as

Surface area = 2lw + 2lh + 2wh

Where

l, w and h are the length, width and height of the cuboid.

Considering the cuboid at the top, its base will not be added. Therefore, the surface area would be

lw + 2lh + 2wh

= 5 × 5 + 2(8 × 5) + 2(8 × 5)

= 25 + 80 + 80

= 185 in²

Considering the box at the base, we would determine the surface area and subtract the area of the base of the first box.

Surface area of bottom box is

2(10 × 10) + 2(10 × 2) + 2(10 × 2)

= 200 + 40 + 40 = 280 in²

The area of the base of the first box is 5 × 5 = 25 in²

Surface area of the bottom box is 280 - 25 = 255 in²

Total surface area of the design is

Area of first box + area of second box

= 185 + 255 = 440 in²

correct answer:

i^31 = -i