How does f(x) = 3* change over the interval x = 4 to x = 57
f(x) increases by 3
f(x) decreases by 3
f(x) increases by a factor of 3
D)
f(x) decreases by a factor of 3
Please help me

f(x) increase by a factor of 3

Explanation:

        Given that f(x)= 3* and the interval is x=4 to x=57

        Now we put the value for x is 4 to 57 then value of f(x) increase with the multiply of 3.

        Because the x is multiplied with 3 i.e., 3*

        So f(x) increase by a factor of 3.

        If we put x=4, then f(x)= 12     (∵ 3×4=12)

        If we put x=5, the f(x)= 15       (∵ 3×5=15)

        If we put x=6,the f(x)= 18             (∵ 3×6=18)

similarly., values of x= 7,8,9,...155.

        Then,

        If we put x=56, the f(x)=168

        This process will continue until f(x)=171 for x=57.

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

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6 purchases

if you are asking how many of each then:

18 social media ads

6 newspaper ads