A(t) = (t – k)(t - 3)(t - 6)(t + 3) is a polynomial function of t, where k is a constant.
Given that a(2) = 0, what is the absolute value of the product of the zeros of a?

the absolute value of the product of the zeros of a is .

Step-by-step explanation:

Here we have , is a polynomial function of t, where k is a constant.  Given that a(2) = 0 . We need to find the  absolute value of the product of the zeros of a . Let's find out:

Equation every factor of a(t) to zero we get:

⇒

⇒

⇒

But , t=2 So ,  . Now , the absolute value of the product of the zeros of a is :

⇒

⇒

⇒

Therefore, the absolute value of the product of the zeros of a is .

step by step explanation: when u removing the parentheses and combined them that would be : x+3y-x-y=2y

c.

step-by-step explanation:

simple you would first have to get   a negative number where as 1 to be multiplied by 24 and then you would have to multiply 6 time 4 and then repeat that process until you reach your term