The given line passes through the points (0, -3) and (2, 3).
What is the equation, in point-slope form, of the line that is
parallel to the given line and passes through the point
(-1, -1)?
(2.3)
y+ 1 = - 3(x + 1)
y+1=-{}(x + 1)
y+1 = {(x + 1)
y+ 1 = 3(x + 1)

y + 1 = 3( x + 1)

Step-by-step explanation:

We are asked to find the equation of the line in point-slope form

Step 1 : find the slope using the two points given

( 0 , -3) ( 2,3)

m = (y_2 - y_1) / (x _2 - x_1)

x_1 = 0

y_1 = -3

x_2 = 2

y_2 = 3

Insert the values into

m = 3 - (-3) / 2 - 0

m = 3 +3 / 2 - 0

= 6/2

= 3

Step 2: it was given in the question that the parallel to a given line and passes through ( -1 , -1)

Substitute the point into the equation

y - y_1 = m ( x - x _1)

m = 3

y - y_1 = 3 ( x - x_1)

x_1 = -1

y_1 = -1

y - (-1) = 3( x - (-1)

y +1 = 3 ( x + 1)

We don't need to open the bracket because we are asked to give the answer in a point-slope form

The equation of the line in point slope form is

y + 1 = 3( x + 1)

goog may have it for you